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Car A starts from rest at t = 0 and travels along a straight road with a constant acceleration of 6 ft/s2 until it reaches a speed of 80 ft/s. Afterwards it maintains this speed. Also, when t = 0, car B located 6000 ft down the road is traveling towards A at a constant speed of 60 ft/s. Determine the distance traveled by car A when they pass each other.

Respuesta :

jayilych4real

The distance traveled by car A when they pass each other is 1071m

Calculations and Parameters

Given:

t=0

constant acceleration= 6 ft/s^2

speed= 80 ft/s^2

[tex]S_A= \frac{at1^2}{2} + V_At\\S_B= V_B (t1 +t)[/tex]

= [tex]2 * (\frac{27}{2})^{2}/2 + 27 * 32.9[/tex]

= 1071m

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