Respuesta :

a(1) =7
d=11-7= 4
a(26)= a(1)+d(n-1)= 7+4(26-1)=7+100=107

S(n)=  (n/2)*(a(1) +a(n))
S(26)=(26/2)*(7+107)=13*114=1482
S(26)=1482
Answer: 1482

The sum of the first 26 terms with common difference 4 is 1482.

What is an arithmetic sequence?

An arithmetic sequence has a first term (a) and the common difference.

From the sequence:

a = 7;

common difference (d) = 11 - 7 = 4

The sum of the first 26 terms is:

[tex]S_{26}=\frac{n}{2}(2a+(n-1)d)=\frac{26}{2}(2(7)+(26-1)4= 1482[/tex]

The sum of the first 26 terms with common difference 4 is 1482.

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