Respuesta :

HomertheGenius
In this case:  x 1 = - 10,  y 1 = - 2;
x 2 = - 4 ,  y 2 = - 2
The distance between the points :
[tex]d = \sqrt{(x 2 - x 1 ) ^{2} + ( y 2 - y 1 ) ^{2} } = \\ =\sqrt{(-4+10) ^{2} +(-2+2) ^{2} } = \\ = \sqrt{6 ^{2}+0 ^{2} } = \sqrt{36}= 6 [/tex]
Answer: d = 6
arojik

In this case:  x 1 = - 10,  y 1 = - 2;

x 2 = - 4 ,  y 2 = - 2

The distance between the points :

d =  \sqrt{(x 2 - x 1 ) ^{2} + ( y 2 - y 1 ) ^{2} } = \\  =\sqrt{(-4+10) ^{2} +(-2+2) ^{2} } = \\ = \sqrt{6 ^{2}+0 ^{2}  } = \sqrt{36}= 6  

Answer: d = 6

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