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For the chemical reaction 2KI+Pb(NO3)2⟶PbI2+2KNO3 how many moles of lead(II) iodide (PbI2) are produced from 8.0 mol of potassium iodide (KI)? number of moles: mol

Respuesta :

Answer:

the number of moles is 6

Explanation:

The computation of the number of moles is given below:

According to the question

Since 2 mol of KI produces 1 mol of PbI2

based on the above information  

The number of moles would be  

8 mol will produce 6 mol of PbI2

Therefore the number of moles is 6

Hence, the same is considered and relevant too

The other things would be ingored

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