Answer:
We can assume that there are no evolutionary changes.
Explanation:
The Hardy-Weinberg Equilibrium is a law which suggests that if the allele frequencies or genotype frequencies do not change in between different generations, then there is no evolutionary influence on that species.
In the example given in the question, it is stated that the genotype frequencies stay the same for the second generation, so according to Hardy-Weinberg equilibrium we can assume that there are no evolutionary changes.
I hope this answer helps.
Answer:
mating in this population is random
Explanation:
In very simple terms, population genetics involves analyses of
the interactions between predictable, "deterministic"
evolutionary forces and unpredictable, random, "stochastic"
forces. The deterministic forces are often referred to as
"linear pressures" because they tend to push allele frequencies
in one direction (up, down or towards the middle).
The Hardy–Weinberg principle states that allele and genotype
frequencies in a population will remain constant from generation to
generation in the absence of other evolutionary influences. These
influences include genetic drift , mate choice , assortative mating ,
natural selection , sexual selection , mutation , gene flow , meiotic
drive , genetic hitchhiking, population bottleneck , founder effect and
inbreeding .
In the simplest case of a single locus with two alleles denoted A
and a with frequencies f (A) = p and f (a) = q , respectively, the
expected genotype frequencies under random mating are f (AA) = p 2
for the AA homozygotes , f (aa) = q 2 for the aa homozygotes, and f
(Aa) = 2 pq for the heterozygotes . In the absence of selection,
mutation, genetic drift, or other forces, allele frequencies p and q are
constant between generations, so equilibrium is reached.
