A rechargeable battery is capable of delivering a current of 0.25 A for 1800 s at a potential difference of 1.5 V.
Calculate :
a. the total charge the battery is capable of delivering without being recharged,
b. the energy transferred from the battery as a result of delivering the charge calculated in part a

Respuesta :

Answer:

a. q=450 c

b. E=675 J

Explanation:

Direct Current (DC)

It's the flow of electric charges in one direction driven by a constant voltage circuit. The intensity of the current flow is computed as

[tex]\displaystyle I=\frac{q}{t}[/tex]

Where q is the constant flow of charge in time t

The energy of an element providing Voltage V, current I during a time t is

[tex]E=V.I.t[/tex]

a. The charge can be computed by solving the first equation for q

[tex]q=I.t=0.25\ A.\ 1800\ s=450\ c[/tex]

b. The energy transferred by the battery is

[tex]E=(1.5).(0.25).(1800)=675\ J[/tex]