Respuesta :
[tex]Q=cm \Delta T \ \ \ \ \ \Rightarrow \ \ \ c=\frac{Q}{m\Delta T}\\\\
Q=183J\\
m=18,5g\\
\Delta T=78,6^{o}C-35^{o}C=43,6^{o}C\\\\
c=\frac{183J}{18,5g*43,6^{o}C}\approx0,227\frac{J}{g^{o}C}[/tex]
Answer:
0.227 J/g°C
Explanation:
Specific heat is the heat change by one gram of substance if it is subjected to change of 1 degree celsius.
The relation between specific heat and mass and change in temperature is:
Q = heat change = mass X specific heat X change in temperature.
Given:
Q = 183 J
Mass = 18.5g
increase in temperature = 78.6-35 = 43.6 °C
Putting values
183 = 18.5X specific heat X 43.6
Specific heat = [tex]\frac{183}{18.5X43.6}= 0.227[/tex][tex]\frac{J}{g^{0}C}[/tex]