ANSWER
[tex]x = 4[/tex]
and
[tex]y = - 1[/tex]
EXPLANATION
Line s has equation:
y=x-5
And line t has equation:
[tex]y = - \frac{3}{4}x + 2[/tex]
We equate the two equations to get:
[tex]x - 5 = - \frac{3}{4} x + 2[/tex]
Multiply through by 4
[tex]4x - 20 = - \frac{3}{4} x \times 4 + 2 \times 4[/tex]
[tex]4x - 20 = - 3 x + 8[/tex]
[tex]4x + 3x = 8 + 20[/tex]
7x=28
[tex]x = \frac{28}{7} = 4[/tex]
[tex]y = 4 - 5 = - 1[/tex]
Answer:
(4, -1) is the solution of the system of equations.
Step-by-step explanation:
A system of equations consists of a line y = x - 5 and a line passing through two points (0, 2) and (8, -4)
And the equation of that passes through these points will be [tex]y=-\frac{3}{4}x+2[/tex]
Now we have to find the solution of the system of linear equations.
By equating both the equations
x - 5 = [tex]-\frac{3}{4}x+2[/tex]
Now we multiply this equation by 4
4(x - 5) = -3x + 4×2
4x - 20 = -3x + 8
4x + 3x = 8 + 20
7x = 28
x = 4
Now we put x = 4 in the equation y = x - 5
y = 4 -5
y = -1
Therefore, (4, -1) is the solution of the system of equations.
