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A ball is kicked off a cliff that is 19.6 m tall. The horizontal speed given to the ball is 12 m/s. How far out from the base of the cliff with the ball land?

Respuesta :

Jenner1256
D=(1/2)gt^2 where g = 9.8 m/s^2


The time down from the 19.6m cliff is
19.6 = 1/2(9.8)t^2
19.6/4.9 = t^2
Square root 90.4 = about 9.8 sec.
12 m/s x 9.8 sec = 117.8 m

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