Read the following conjecture.

Any number that is divisible by 3 is also divisible by 9.

Find a counterexample to show that the conjecture is false.

18
27
48
45

Respuesta :

48 is not a multiple of 9 at all and that might be the problem sorry dont really understand it.

Answer:

45

Step-by-step explanation:

We have to prove that any number that is divisible by 3 need not be divisible by 9

To show that conjecture that any number that is divisible by 3 is also divisible by 9 we have to show an counter example.

THe four options given are 18, 27, 48 and 45.

Out of these 4 numbers, 18, 27, 45 are divisible by both 3 and 9.

Hence these numbers cannot be shown as counter example.

Take the case of 48

48 is divisible by 3 as 48 =16(3)

But 48 is not divisible by 9.

Thus 45 is a good counterexample to prove number that is divisible by 3 is also divisible by 9 is false.