Respuesta :
. Anne has 3 sisters
. she buys each sister a necklace
. 1 necklace = $7
. she has $9 left after buying the necklaces
necklace=a
money had to spend per sister= b
3a + 9 = b×3
3×a + 9 = b×3
3×7 + 9 = b×3
21 + 9 = b×3
30 = b×3
30 ÷ 3 = b
10 = b
Anne initially had $10 to spend on each sister.
. she buys each sister a necklace
. 1 necklace = $7
. she has $9 left after buying the necklaces
necklace=a
money had to spend per sister= b
3a + 9 = b×3
3×a + 9 = b×3
3×7 + 9 = b×3
21 + 9 = b×3
30 = b×3
30 ÷ 3 = b
10 = b
Anne initially had $10 to spend on each sister.
The equation that represent how much Anne had initially to spend is x - 21 = 9 and the money she had initially is 30 dollars.
How to use equation to find the amount Anne had initially to spend?
She bought a necklace for each of her three sisters. She paid $7 for each of the necklace. she had 9 dollars left after the expenditure.
Therefore,
let the money she had initially = x
Hence,
x - 7(3) = 9
x - 21 = 9
x = 21 + 9
x = 30
Therefore, the money she had initially to spend on each sister was 30 dollars.
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