Answer:
The value of sin B is 5/13.
Step-by-step explanation:
In , Right triangles ABC:
∠A + ∠B = 90° (complimentary angles)
∠C = ?
In ΔABC:
∠A + ∠B + ∠C = 180° (angle sum property)
90° + ∠C = 180°
∠C= 180° - 90° = 90°
So, in right triangles ABC, angle 90° is at C.
According to trigonometric ratios:
[tex]\cos \theta =\frac{base}{hypotenuse}[/tex]
In right triangle ABC with base AC:
[tex]\cos A=\frac{5}{13}=\frac{AC}{AB}[/tex]
AC = 5. AB = 13
In right triangle ABC with base BC, then perpendicular becomes AC and hypotenuse is AB.
According to trigonometric ratios:
[tex]\sin\theta =\frac{perpendicular}{hypotenuse}[/tex]
[tex]\Sin B=\frac{5}{13}[/tex]
The value of sin B is 5/13.
