How many grams of Cu will be produced when 10 grams of Al reacts with CuCl2 in the following chemical reaction? Al(s) + CuCl2(aq)→ AlCl3(aq) + Cu(s). Use the Equation Balancer tool to balance the equation and find the mole ratio of Cu:Al. The molar masses Al, Cu, and CuCl2 are 26.98 grams, 63.55 grams, and 134.45 grams respectively.

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17-04-2018
Chemistry

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How many grams of Cu will be produced when 10 grams of Al reacts with CuCl2 in the following chemical reaction? Al(s) + CuCl2(aq)→ AlCl3(aq) + Cu(s). Use the Equation Balancer tool to balance the equation and find the mole ratio of Cu:Al. The molar masses Al, Cu, and CuCl2 are 26.98 grams, 63.55 grams, and 134.45 grams respectively.

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11beehshahbaz 11beehshahbaz · Answer 1 · 2018-04-17T20:31:42+02:00

First, we need to write the balanced chemical equation for the given problem.
The balanced equation will be:

2Al + 3CuCl2 → 2AlCl3 + 3Cu

So, according to the balanced equation, 2 moles (53.96 grams) of Al produces 3 moles (190.65 grams) of Cu.

So,

1 gram of Al will produce copper = 190.65/53.96 grams
10 grams of Al will produce copper = 190.65/53.96 x 10 = 35.33 grams

Thus,
10 grams of Al react with CuCl2 to produce 35.33 grams of Cu