Solution:
we are given that
A spherical mini donut hole has a diameter of 6 centimeters.
A large spherical donuts hole has a diameter of 9 centimetres.
we have been asked to find
Approximately how much greater is the volume of a large donuts hole than the volume of a mini donuts hole?
As we know the volume of the sphere is given by the formula
[tex] V=\frac{4}{3} \pi r^3\\
\\
\text{So volume of smaller Spherical(r=6/2=3) hole can be given as }\\
\\
V_1= \frac{4}{3} \pi *3^3\\
\\
\text{So volume of larger Spherical hole(r=9/2=4.5) can be given as }\\
\\
V_1= \frac{4}{3} \pi *4.5^3\\
\\
\text{So Difference in volume}=\frac{4}{3} \pi *4.5^3-\frac{4}{3} \pi *3^3\\
\\
\text{Simplify we get}\\
\\
\text{So Difference in volume} \approx 268 cm^3\\
\\ [/tex]
Hence the correct option is 268 cm^3
