Respuesta :

[tex](0.5n^{5})^2 \cdot (10n^{7})^{3} = 0.5^{2} \cdot n^{10}  \cdot 1000n^{21} = (\frac{1}{2})^{2} \cdot n^{10} \cdot 1000n^{21} = \frac{1}{4}n^{10} \cdot 1000n^{21} = n^{10} \cdot 250n^{21} = 250n^{31}.[/tex]