Respuesta :
(a) Wavelength and frequency of a wave are related by the following equation:
[tex]\lambda= \frac{v}{f} [/tex]
where
[tex]\lambda[/tex] is the wavelength
f is the frequency
v is the speed of the wave.
The speed of sound at room temperature is approximately [tex]v=343 m/s[/tex], so we can find the wavelength corresponding to a frequency of [tex]f=20000 Hz[/tex] by using the previous relationship:
[tex]\lambda= \frac{v}{f}= \frac{343 m/s}{20000 Hz}=0.017 m [/tex]
(b) the lowest sound we can hear has a frequency of f=20 Hz. Using the same relationship we used in the previous part of the exercise, we can find the corresponding wavelength:
[tex]\lambda= \frac{v}{f} = \frac{343 m/s}{20 Hz}=17.15 m [/tex]
[tex]\lambda= \frac{v}{f} [/tex]
where
[tex]\lambda[/tex] is the wavelength
f is the frequency
v is the speed of the wave.
The speed of sound at room temperature is approximately [tex]v=343 m/s[/tex], so we can find the wavelength corresponding to a frequency of [tex]f=20000 Hz[/tex] by using the previous relationship:
[tex]\lambda= \frac{v}{f}= \frac{343 m/s}{20000 Hz}=0.017 m [/tex]
(b) the lowest sound we can hear has a frequency of f=20 Hz. Using the same relationship we used in the previous part of the exercise, we can find the corresponding wavelength:
[tex]\lambda= \frac{v}{f} = \frac{343 m/s}{20 Hz}=17.15 m [/tex]
The wavelength of these sound waves are :
The minimum wavelength is about 0.0173 m
The maximum wavelength is about 17.3 m
[tex]\texttt{ }[/tex]
Further explanation
Let's recall the speed of wave formula as follows:
[tex]\boxed {v = \lambda \times f}[/tex]
where:
c = speed of wave ( m/s )
λ = wavelength ( m )
f = frequency of wave ( Hz )
Let us now tackle the problem!
[tex]\texttt{ }[/tex]
Given:
maximum frequency of sound wave = f_max = 20 000 Hz
minimum frequency of sound wave = f_min = 20 Hz
speed of sound wave in room temperature = v = 346 m/s
Asked:
A) The minimum wavelength = λ_min = ?
B) The maximum wavelength = λ_max = ?
Solution:
Part A:
[tex]\lambda_{min} = v \div f_{max}[/tex]
[tex]\lambda_{min} = 346 \div 20000[/tex]
[tex]\boxed {\lambda_{min} = 0.0173 \texttt{ m}}[/tex]
[tex]\texttt{ }[/tex]
Part B:
[tex]\lambda_{max} = v \div f_{min}[/tex]
[tex]\lambda_{max} = 346 \div 20[/tex]
[tex]\boxed {\lambda_{max} = 17.3 \texttt{ m}}[/tex]
[tex]\texttt{ }[/tex]
Learn more
- Frequency of Sound Wave : https://brainly.com/question/12441470
- Frequency of Beats : https://brainly.com/question/12367463
- Amplitude of Sound Wave : https://brainly.com/question/2675676
- Kinetic Energy : https://brainly.com/question/692781
- Acceleration : https://brainly.com/question/2283922
- The Speed of Car : https://brainly.com/question/568302
[tex]\texttt{ }[/tex]
Answer details
Grade: High School
Subject: Physics
Chapter: Sound Wave
