Answer:
The 1st graph represents the given equation.
Step-by-step explanation:
We are given the equation [tex]y^2=-4x[/tex]
Now, as we know,
If in the equation of a parabola 'y' is squared, then the parabola opens left or right.
So, the given parabola opens left or right. ............(1)
If in the equation of a parabola [tex]y^2=4ax[/tex], the value of 'a' is negative, then the parabola opens downwards or left.
Since, in the given parabola, value of 'a' is -1.
So, the parabola opens downwards or right. ...........(2)
Hence, from (1) and (2), we get,
The parabola [tex]y^2=-4x[/tex] opens to the left.
Moreover, the focus of the parabola [tex](y-k)^2=4p(x-h)[/tex] is (h+p,k) and the directrix is x= -p
So, the focus of [tex]y^2=-4x[/tex] is (0-1,0) i.e. (-1,0) and the directrix is x= 1.
So, the 1st graph represents the given equation.
