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An engineering school reports that 55% of its students were male (m), 40% of its students were between the ages of 18 and 20 (a), and that 25% were both male and between the ages of 18 and 20. what is the probability of a random student being female between the ages of 18 and 20? assume p(f) = p(not m).

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Answer:

I did .30

Step-by-step explanation:

Make a table that you can fill in.

Look at the attached file for the answer.

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Building and solving an equation, it is found that there is a 0.3333 = 33.33% probability of a random student being female between the ages of 18 and 20.

  • 55% of the students are male, 45% female.
  • 40% are between 18 and 20.
  • 25% are both male and between the ages of 18 and 20, the x% of the 45% that is between these ages add to 40%, thus:

[tex]0.25 + 0.45x = 0.4[/tex]

[tex]0.45x = 0.15[/tex]

[tex]x = \frac{0.15}{0.45}[/tex]

[tex]x = 0.3333[/tex]

0.3333 = 33.33% probability of a random student being female between the ages of 18 and 20.

A similar problem is given at https://brainly.com/question/24812278

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