Write a for loop that assigns summedvalue with the sum of all odd values from 1 to usernum. assume usernum is always greater than or equal to 1. ex: if usernum is 5, then summedvalue is 9 (i.e. 1 + 3 + 5 = 9).

Respuesta :

I don't know which language you use those, so I assume that you use c++
for (int i = 1; i <= userNum; i++)
{
      summedValue = summedValue + i;
      i = i + 1;
}

def summedvalue( usernum):

      oddcount = 0

       for num in range (1, usernum + 1):

               if (num % 2 != 0):

                       oddcount = oddtotal + num

      print(oddcount)

sumvalue(10)

I will use python language to write the code.

def summedvalue( usernum):

      oddcount = 0

       for num in range (1, usernum + 1):

               if (num % 2 != 0):

                       oddcount = oddtotal + num

      print(oddcount)

sumvalue(10)

The code is written in python. def is a  key word in python. It is use to declare a function in python. The function is named summedvalue. Then a variable is declared called oddcount.  The variable is assigned an integer 0. The next line, we use a for loop to loop through the range 1 to the usernum(the user number is included). The next line we use the if statement to know if the looped numbers divided by 2 will have a remainder. If it has a remainder, then it is an odd number. The odd number will be added to the oddcount value(0) . The total value of the oddcount is printed out in the next line.

Finally, we call our function with the argument(usernum) . The user number(usernum) can be 1, 2, 3, 4, 5, 6, 7, 8, 9............

Note: pay attention to the indentation. Python uses indentation.

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