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Given that f(x) = 3x^2 − 36, find x.

A) x = ±2 sqrt 2

B) x = ±2 sqrt 3

C) x = ±3 sqrt 2

D) x = ±3 sqrt 3

Respuesta :

B. 
first set it equal to zero: 
3x^2-36 = 0
add 36 to both sides:
3x^2=36
divide by 3 to both sides:
x^2=12
take the square root of 12 and you get factors of 2,2, and 3, so you're answer is b. 

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