Respuesta :
Suppose x books are produced by both methods.
Total cost for method 1 = 60346 + 10.5x
Total cost for method 2 = 18682 + 21x
Cost of method 1 = Cost of method 2
60346 + 10.5x = 18682 + 21x
60346 - 18682 = 21x - 10.5x
41664 = 10.5x
x = 41664/10.5
x = 3968
For 3968 books produced the cost by both methods will be the same.
Total cost for method 1 = 60346 + 10.5x
Total cost for method 2 = 18682 + 21x
Cost of method 1 = Cost of method 2
60346 + 10.5x = 18682 + 21x
60346 - 18682 = 21x - 10.5x
41664 = 10.5x
x = 41664/10.5
x = 3968
For 3968 books produced the cost by both methods will be the same.
Equation :
[tex]10.50x \: + 60346 = 21x \: + 18682[/tex]
Move terms,
[tex]10.5x + 60346 = 21x \\ \: \: \: \: \: \: \: \: \: \: \: \: - \: 18682 =41664 [/tex]
Move terms again,
[tex]41664 = 21x \\ \: \: \: \: \: \: \: \: \: \: \: \: \: - \: 10.5x = 10.5x[/tex]
Rewrite,
[tex]41664 = 10.5x[/tex]
Divide both sides by 10.5x,
[tex]3968 = x[/tex]
~~
Answer :
If 3,968 books are produced the costs form the two methods will be the same.
~~
I hope that helps you out!!
Any more questions, please feel free to ask me and I will gladly help you out!!
~Zoey
[tex]10.50x \: + 60346 = 21x \: + 18682[/tex]
Move terms,
[tex]10.5x + 60346 = 21x \\ \: \: \: \: \: \: \: \: \: \: \: \: - \: 18682 =41664 [/tex]
Move terms again,
[tex]41664 = 21x \\ \: \: \: \: \: \: \: \: \: \: \: \: \: - \: 10.5x = 10.5x[/tex]
Rewrite,
[tex]41664 = 10.5x[/tex]
Divide both sides by 10.5x,
[tex]3968 = x[/tex]
~~
Answer :
If 3,968 books are produced the costs form the two methods will be the same.
~~
I hope that helps you out!!
Any more questions, please feel free to ask me and I will gladly help you out!!
~Zoey