Answer:
Option: c is the correct answer.
c. irrational.
Step-by-step explanation:
On multiplying the two terms as follows:
[tex]\dfrac{4}{3}\times \dfrac{\sqrt{6}}{2}\\\\\\=\dfrac{4\sqrt{6}}{6}\\\\\\=\dfrac{4}{\sqrt{6}}\\\\\\=\dfrac{2\sqrt{2}}{\sqrt{3}}[/tex]
As we could observe that the result of the multiplication contain a square root term.
Hence, the number is not an integer.
Also, it is not an rational number.
( Since its decimal expansion is non-terminating)
Hence, the answer is: It is an irrational number.
