Circle A and circle B are congruent. CD is a chord of both circles. If AB = 24 in. and the radius is 13 in., how long is CD?

The value of the chord CD will be equal to 10 inches.
Circle is a round plane figure whose boundary (the circumference) consists of points equidistant from a fixed point (the centre).
Now it is given in the question that The length AB=24 In so the half of ab will be the base of the triangle COA so OA=12 in
Now the Hypotenuse of the OA will be =13 In
So in triangle COA by pythgorous theorem we will get
[tex]\rm CA^2=CO^2+OA^2[/tex]
[tex]\rm 13^2=CO^2+12^2[/tex]
[tex]\rm CO^2=169-144=25[/tex]
[tex]\rm CO=\sqrt{25}=5 \ in[/tex]
Since the value of CD=2CO then CD=2*5=10 in
So the value of the chord CD will be equal to 10 inches.
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