Respuesta :
For the first drawing, there are 30 tickets altogether, and Jason
has 10 of them. The probability that one of his tickets will win is
10 / 30 .
For the second drawing, there are 29 tickets altogether, and Jason
has 9 of them. The probability that one of his tickets will win is
9 / 29 .
For the third drawing, there are 28 tickets altogether, and Jason
has 8 of them. The probability that one of his tickets will win is
8 / 28 .
The probability that all three of these things will happen is
(10/30) x (9/29) x (8/28) = 720 / 24,360
= 6 / 203 = 2.96 percent (rounded)