Respuesta :
so James covers 8 meters in the first second....then he sprints 9 meters per second......
9 seconds after the race....so there are 8 seconds that he is sprinting 9 meters per second.....(8 * 9) = 72 meters....plus the 8 meters for the 1st second = (72 + 8) = 80 meters....
and if it is 100 meter race, and he has ran 80 meters, then that leaves 20 meters from the finish line....answer is D
9 seconds after the race....so there are 8 seconds that he is sprinting 9 meters per second.....(8 * 9) = 72 meters....plus the 8 meters for the 1st second = (72 + 8) = 80 meters....
and if it is 100 meter race, and he has ran 80 meters, then that leaves 20 meters from the finish line....answer is D
Answer:
Option b. 20 meters
Step-by-step explanation:
James covers a distance of 8 meters in the first second of 100 meter race.
Then, he sprints at a speed of 9 meters per second.
We have to find how far is James from the finish line 9 seconds after the start of the race.
James covers distance in first second = 8 meters.
Time remaining in 9 seconds after running 8 meter = 9 - 1 = 8 seconds.
In another 8 seconds James covers the distance = speed × time
= 9 × 8 = 72 meters
Total distance covered in 9 seconds = 8 + 72 = 80 meters
Distance remaining in 100 meter race after 9 seconds = 100 - 80 = 20 meters.
James is 20 meters far from the finish line 9 seconds after the race has started.
Option b. 20 meters is the answer.