a square and a rectangle are isoperimetric and have a perimeter of 80 cm. knowing that the height of the rectangle exceeds the bases of 12 cm, calculates the area of each figure.
[364cm2; 400cm2]
each side of the square would be 80/4 = 20 cm. so its area = 20^2 = 400 cm^2. Th rectangle will have perimeter = 80 = 2x + 2(x - 12) where x = height of the rectangle 4x = 80+24 = 104 so x = 26 area of rectangle = 26*(26-12) = 364 cm^2
