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Find the complete factorization of the expression.

10xyz + 24xy + 6xz
A) xyz(5 + 12 + 3)
B) 2x(5zy + 12y + 3z)
C) x(10zy + 24y + 6z)
D) 2(5xzy + 12xy + 3xz)

Respuesta :

it well be B.) they all have a factor of 2
jhonlopera05

Answer:

B) 2x(5zy + 12y + 3z)

Step-by-step explanation:

First, all coefficient for each term are a pair number, therefor 2 is common factor for all these

[tex]10xyz + 24xy + 6xz=>2(5zxy + 12xy + 3xz )[/tex]

then, the variable X is present for each term of the funtion [tex](5zxy + 12xy + 3xz)[/tex], so, the variable X is a common factor to.

[tex]2(5zxy + 12xy + 3xz )=> 2x(5zy + 12y + 3z )[/tex]

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