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Denise is conducting a physics experiment to measure the acceleration of a falling object when it slows down and comes to a stop. She drops a wooden block with a mass od 0.5 kilograms on a sensor on the floor. The sensor measures the force of the impact as 4.9 newtons. Whats the acceleration of the wooden block wgen it hits the sensor

Respuesta :

we need a and we have m and F . Now a = f÷m so therefore a = 4,9 ÷ 0,5 which is 0,98 metres per cubic second

Answer:

[tex]a = 9.8 m/s^2[/tex]

Explanation:

As we know that here given parameters are

[tex]mass = 0.5 kg[/tex]

also we know that force of impact on the floor is given as

[tex]F = 4.9 N[/tex]

now we know by the Newton's 2nd law says that the net force on an object is product of mass and its acceleration

it is given by

[tex]F = ma[/tex]

now we have

[tex]a = \frac{F}{m}[/tex]

[tex]a = \frac{4.9}{0.5}[/tex]

[tex]a = 9.8 m/s^2[/tex]

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