1. Points M and N have coordinates (-4,0) and (4,2), respectively.
Then vector [tex]\overrightarrow{MN}=(4-(-4),2-0)=(8,2)[/tex] is perpendicular to the neede line.
2. Write the equation of line that passes through the point P(2,-4) and is perpendicular to vector [tex]\overrightarrow{MN}=(8,2):[/tex]
[tex]8(x-2)+2(y+4)=0,\\8x-16+2y+8=0,\\8x+2y-8=0,\\4x+y-4=0.[/tex]
3. Find the point on x-axis, that lies on the perpendicular line.
When y=0, then 4x-4=0, x=1 and point (1,0) lies on perpendicular line.
Answer: correct choice is C.
