if the population of state is 1,821,000 decreasing by 0.2% every year what will the population be in 5 years PLEASE PLEASE HELP

Respuesta :

that would be  1,821,000(1 - 0.002)^5  = 1.802,862  answer

(Note 2%  = 0.002 as a decimal fraction.)

Answer:

1,802,862.

Step-by-step explanation:

We have been given that the population of state is 1,821,000 decreasing by 0.2% every year. We are asked to find the population of state after 5 years.

We will use exponential decay function to solve our given problem.

[tex]y=a\cdot b^x[/tex], where,

y = Amount left after x years,

a = Initial amount,

b = For decay b is in form (1-r) where r represents decay rate in decimal form.

x = Number of years.

Let us convert our given rate in decimal form.

[tex]0.2\%=\frac{0.2}{100}=0.002[/tex]

Upon substituting our given values in above formula we will get,

[tex]y=1,821,000 \cdot(1-0.002)^5[/tex]

[tex]y=1,821,000 \cdot(0.998)^5[/tex]

[tex]y=1,821,000 \cdot 0.990039920079968[/tex]

[tex]y=1,802,862.69[/tex]

Since we can not have 0.69 of a person, therefore, we will round down our answer.

[tex]y=1,802,862.69\approx 1,802,862[/tex]

Therefore, the population of state after 5 years will be 1,802,862.