Respuesta :
The figure shown below illustrates the seating area.
The radius of the two semicircular areas is r = 1000 cm = 1 m.
The top rectangle has dimensions 40 m by 2 m.
One bottom rectangle has the dimensions 25 m by 0.8 m.
The other bottom rectangle has dimensions 10 m by 0.8 m.
The perimeter of the pitch and seating area is
P = 2π(1) + 40 + 4(0.8) + 40 = 83.2 + 2π m = 89.483 m
The total area is
A = π(1) + 40(2) + 25(0.8) + 10(0.8) = 111.1416 m²
Answers:
Perimeter = 89.5 m (nearest tenth)
Area = 111.1 m² (nearest tenth)
The radius of the two semicircular areas is r = 1000 cm = 1 m.
The top rectangle has dimensions 40 m by 2 m.
One bottom rectangle has the dimensions 25 m by 0.8 m.
The other bottom rectangle has dimensions 10 m by 0.8 m.
The perimeter of the pitch and seating area is
P = 2π(1) + 40 + 4(0.8) + 40 = 83.2 + 2π m = 89.483 m
The total area is
A = π(1) + 40(2) + 25(0.8) + 10(0.8) = 111.1416 m²
Answers:
Perimeter = 89.5 m (nearest tenth)
Area = 111.1 m² (nearest tenth)
