Answer:
[tex]1.\rightarrow -2 \frac{1}{3}-(-10) \frac{1}{6}\\\\\rightarrow \frac{-7}{3} -\frac{-61}{6}\\\\\rightarrow \frac{-14+61}{6}\\\\\rightarrow \frac{47}{6}\\\\\rightarrow 7\frac{5}{6}[/tex]
Option C→Seven and five-sixths
2.
(-3) +(-5)
Mark -3 and -5 on the number line.Move 5 units left of -3 to reach at -8.That is required sum.
3.
Distance between −12 and −15 on the number line is given by
|-12 -(-15}| or |-15 -(-12)|
=|-12+15| or |-15+12|
=|3| or |-3|
=3 units
Option C
|−12 − (−15)| = 3
