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The vapor pressure of benzene is 100.0 mmhg at 26.1°c. calculate the vapor pressure of a solution containing 28.2 g of camphor (c10h16o) dissolved in 94.8 g of benzene. (camphor is a low-volatility solid.

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Kalahira
Answer: Moles C10H16O = 24.6 g/ 153.23 g/mol = 0.161 Moles benzene = 98.5 g / 78.1121 g/mol = 1.26 Mole fraction benzene = 1.26 / 1.26 + 0.161 = 0.887 vapor pressure = 100 x 0.887 = 88.7 mm Hg

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