Respuesta :
The sum of 4 consecutive integers is 198. What is the fourth number in this sequence?

Answer: 51.
Step-by-step explanation:
Let the four consecutive be x , x+1 , x+2 , x+3 ,x+4.
Then , According to the given question, we have
[tex]x+x+1+x+2+x+3=198\\\\\Rightarrow\ 4x+6=198\\\\\Rightarrow\ 4x=198-6\\\\\Rightarrow\ 4x=192\\\\\Rightarrow\ x=\dfrac{192}{4}\\\\\Rightarrow\ x=48[/tex]
Now, the fourth number will be :-
[tex]48+3=51[/tex]
Hence, the fourth number will be 51.