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Find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation. If y varies inversely as the square of x, and y=1/8 when x=1 find y when x=5

Respuesta :

y=k/x²; substitute x=1 and y=1/8: 1/8=k. So y=1/(8x²)
When x=5, y=1/(8×25)=1/200.

Answer:

B

Step-by-step explanation:

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