Answer:
The new pressure is 285 kPa
Explanation:
Given:
Initial pressure of the tire, P1 = 325 kPa
Initial Temperature, T1 = 10 C
Final Temperature, T2 = 50 C
To determine:
The final pressure of the tire, P2
Explanation:
Based on the ideal gas equation
[tex]PV = nRT[/tex]
where P = pressure, V = volume ; n = moles of gas
R = gas constant, T = temperature
At constant n and V, the above equation becomes:
P/T = constant
This is the Charles law
Therefore:
[tex]\frac{P1}{T1} = \frac{P2}{T2} \\\\P2 = \frac{P1}{T1} *T2 = \frac{325 kPa*(10+273)K}{(50+273)K} =285 kPa[/tex]
