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A wooden box weighing 150 N is sliding at a constant rate over a concrete sidewalk. The force required to pull the box at a steady rate is 78 N. What is the coefficient of friction?

Respuesta :

Box is moving at constant velocity. Therefore, net force on the wooden box is zero.

f = μN 
78 = μ(mg)
μ = 78/150 = 0.52
Therefore, coefficient of friction is 0.52

Answer:

The coefficient of friction is 0.52

Explanation:

Weight of the box, W = N = 150 N

The force required to pull the box at a steady rate is 78 N, F = 78 N

In horizontal direction, the net force acting on the box is given by :

[tex]F-\mu N=0[/tex]

[tex]F=\mu N[/tex]

[tex]\mu=\dfrac{F}{N}[/tex]

[tex]\mu=\dfrac{78}{150}[/tex]

[tex]\mu=0.52[/tex]

So, the coefficient of friction is 0.52. Hence, this is the required solution.

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