Answer:
Sn = 78.77%
O = 21.23%
Explanation:
The atomic mass of Sn = 118.71 g/mol
The atomic mass of O = 16 g/mol
The molar mass of SnO₂ = atomic mass of Sn + 2 X atomic mass of O
The molar mass of SnO₂= 150.71
Now, in each mole of SnO₂ there is one mole of Sn and two moles of O
The mass of Sn in 150.71 g of SnO₂ = 118.71
Percentage of Sn in 150.71 g of SnO₂ = [tex]\frac{MassofSnX100}{massofSnO_{2} }[/tex]
% of Sn = [tex]\frac{118.71X100}{150.71}=78.77[/tex]%.
Rest will be O = 100-78.77 = 21.23%
