x(x + 3) + 34 = (x + 5)(x + 2)
First, expand to remove parentheses.
[tex] x^{2} + 3x + 34 = x^{2} + 2x + 5x + 10[/tex]
Second, add '2x + 5x' to get '7x'.
[tex] x^{2} + 3x + 34 = x^{2} + 7x + 10[/tex]
Third, cancel out '[tex] x^{2} [/tex]' on both sides.
[tex]3x + 34 = 7x + 10[/tex]
Fourth, subtract '3x' from both sides.
[tex]34 = 7x + 10 - 3x[/tex]
Fifth, subtract '7x - 3x' to get '4x'.
[tex]34 = 4x + 10[/tex]
Sixth, subtract '10' from both sides.
[tex]34 - 10 = 4x[/tex]
Seventh, subtract '34 - 10' to get '24'.
[tex]24 = 4x[/tex]
Eighth, divide both sides by '4', leaving the 'x' by itself.
[tex] \frac{24}{4} =x[/tex]
Ninth, since '24 ÷ 4 = 6', simplify the fraction to '6'.
[tex]6 = x[/tex]
Tenth, switch your sides to get the answer.
[tex]x = 6[/tex]
Answer: x = 6
