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The sum of a number and 20 is no more than the sum of the square of the number and 9. Which of the following inequalities can be used to determine this unknown number?

Respuesta :

lizywflvs
x+20>x3^+9 i think, idk tho

Answer:

[tex]x + 20 \leq \sqrt{x} + 9[/tex]

Explanation:

The number is x.

The sum of a number and 20 is no more than the sum of the square of the number and 9.

This means that the sum of x and 20 is lesser or equal than the sum of the square of x and 9. So:

[tex]x + 20 \leq \sqrt{x} + 9[/tex]

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