Answer:
[tex]2.16 \cdot 10^5 N/C[/tex]
Explanation:
The strength of the electric field produced by the single charge is given by
[tex]E=\frac{kq}{r^2}[/tex]
where
[tex]k=8.99\cdot 10^9 N m^2 C^{-2}[/tex] is the Coulomb's constant
[tex]q = 6 \mu C = 6 \cdot 10^{-6} C[/tex] is the charge
[tex]r = 0.5 m[/tex] is the distance from the charge at which we want to calculate the field strength
Substituting the numbers into the equation, we find
[tex]E=\frac{(8.99\cdot 10^9 )(6 \cdot 10^{-6} C)}{(0.5 m)^2}=2.16\cdot 10^5 N/C[/tex]
