Answer: The required probability that the child took a green marble is 40%.
Step-by-step explanation: Given that there are 9 red and 6 green marbles in a bag and a child reaches in the bag and randomly takes one marble.
We are to find the probability that the child took a green marble.
Let S denote the sample space of choosing a marble from the bag and A be the event of choosing a green marble.
Then,
n(S) = 9 + 6 = 15 and n(A) = 6.
Therefore, the probability of event A will be
[tex]P(A)=\dfrac{n(A)}{n(S)}=\dfrac{6}{15}=\dfrac{2}{5}\times 100\%=40\%.[/tex]
Thus, the required probability that the child took a green marble is 40%.
