Respuesta :
S=f+60
J=Fx2-50
Senior=fx3
(f)+(f+60)+(fx2-50)+(fx3)=1424 (Parenthesis first)
f+f+60+2f-50+3f=1424 (rewrite)
2f+60+2f-50+3f=1424 (combine like variables)
7f+10=1424 (rewrite)
7f=1414 (isolate variable (take away 10 from each side))
1414/7
202=freshman
J=Fx2-50
Senior=fx3
(f)+(f+60)+(fx2-50)+(fx3)=1424 (Parenthesis first)
f+f+60+2f-50+3f=1424 (rewrite)
2f+60+2f-50+3f=1424 (combine like variables)
7f+10=1424 (rewrite)
7f=1414 (isolate variable (take away 10 from each side))
1414/7
202=freshman
Answer:
The number of students in the freshman class are:
202
Step-by-step explanation:
Let the number of students in Freshman class = x
- The sophomore class has 60 more students than the freshman class.
This means that the number of students in sophomore class = x+60
- The junior class has 50 fewer students than twice the students in the freshman class.
This means that the number of students in junior class= 2x-50
- The senior class is three times as large as the freshman class.
This means that the number of students in senior class are: 3x
- There are a total of 1,424 students at the city high school.
This means that:
[tex]x+x+60+2x-50+3x=1424\\\\x+x+2x+3x+60-50=1424\\\\7x+10=1424\\\\7x=1424-10\\\\7x=1414\\\\x=\dfrac{1414}{7}\\\\x=202[/tex]