Respuesta :

Since the order of the books chosen doesn't matter, we use the combination formula to find the number of possible selections. Recall that a combination of k items from a set of n items is given by   [tex]nCk= \frac{n!}{k!(n-k)!} [/tex]. 

In this problem, n = 8 and k = 3. So the number of possible selections is 
[tex]8C3= \frac{8!}{3!(8-3)!}=56 [/tex]. Thus the answer is 56.
W0lf93
The student has 6,720 selections to choose from. Because order doesn’t matter, the problem is a combinations function. It is solved by dividing the factorial of 8 by the factorial of 3. So (8*7*6*5*4*3*2*1)/(3*2*1)

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