how many times longer is the baby alligator 3/4 ft than the baby 2/15ft

1. Find common denominators so the common denominator is 60
2. Multiply the numerator by how much the denominator goes into the common denominator so 3 x 15 and 2 x 4
3.You get left with 45/60 - 8/60
4. Subtract the numerators to get 37/60
5. You can't simplify it so the final answer is 37/60

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boffeemadrid boffeemadrid · Answer 2 · 2021-10-22T10:29:29+02:00

We need to find how much longer is the baby alligator compared to a baby.

The baby alligator is [tex]\dfrac{45}{8}[/tex] times longer than the baby.

The baby alligator is 3/4 ft long.

The baby is 2/15 ft long.

According to the question

[tex]\dfrac{3}{4}=\dfrac{2}{15}x[/tex]

The value of x will give us how many times is the baby alligator longer by

[tex]x=\dfrac{\dfrac{3}{4}}{\dfrac{2}{15}}\\\Rightarrow x=\dfrac{3\times 15}{4\times 2}\\\Rightarrow x=\dfrac{45}{8}[/tex]

So, the baby alligator is [tex]\dfrac{45}{8}[/tex] times longer than the baby.

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