jamesg860 jamesg860

17-10-2017
Mathematics

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find the possible value or values of y in the quadratic equation z^2 - 4z+ 4 =0

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altavistard altavistard

17-10-2017

Didn't you mean "Find the possible value or values of z? y is not at all present in this equation.

z^2 - 4z + 4 = 0 can be factored into (z-2)(z-2). Thus, the given equation has two equal, real solutions: z=2 and z=-2.

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