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Part
b.1. eliseo couldn't find the 6 m hcl and so used 6 m hno3 for testing the metals instead. his logic? both are strong acids. explain how the results of the experiment would have been different.

Respuesta :

shinmin
We all know that HNO3 should have not been used in this redox titration because being an oxidizing agent it corrodes the compound itself while HCL is a very unstable or volatile and it takes slice in the response. And the final outcome would have produced a blue solution, whereas there would really be no reaction had he used the 6 M HCl as taught.

If Eliseo used the 6 M HNO3 for the substitution for 6M HCI, thus the product would have yielded a blue solution, whereas there would actually no reaction had he used the 6 M HCI as instructed. Being a good oxidizing agent it oxidizes the compound itself whereas HCL takes part in the reaction and is very volatile, thus HNO3 should have not been used in redox titration.

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