This question is based on the graph. Therefore, these are the points for first curve ( 0, 3) and ( [tex]\dfrac{\pi}{5}[/tex], -3) for plotting the graph and these are the points ( 0, 0) and ( [tex]\dfrac{\pi}{5}[/tex], 6) for plotting the graph.
Given:
y = 3 cos(5x),
y = 3 − 3 cos(5x), 0 ≤ x ≤ π/5
In this question we have to sketch the region enclosed by the given curves.
- y = 3 cos(5x),
- y = 3 − 3 cos(5x), 0 ≤ x ≤ π/5
Now we have to plotting the graphs of both the curves.
For first curve: y = 3 cos(5x), 0 ≤ x ≤ π/5
Putting x = 0 in first equation.
We get,
y = 3
Now putting x = [tex]\dfrac{\pi}{5}[/tex] in first equation.
We get,
y = -3
Therefore, these are the points ( 0, 3) and ( [tex]\dfrac{\pi}{5}[/tex], -3) for plotting the graph.
Now for second curve: y = 3 − 3 cos(5x), 0 ≤ x ≤ π/5
Putting x = 0 in first equation.
We get,
y = 0
Now putting x = [tex]\dfrac{\pi}{5}[/tex] in first equation.
We get,
y = 6
Therefore, these are the points ( 0, 0) and ( [tex]\dfrac{\pi}{5}[/tex], 6) for plotting the graph.
For more details, prefer this link:
https://brainly.com/question/10712002
