Respuesta :
Explanation:
The given data is as follows.
acceleration (a) = 20 mph
time (t) = 30 sec
initial velocity (u) = 0
As 1 mph = 0.447 m/s. So, convert 20 mph into m/s as follows.
[tex]20 mph/s \times \frac{0.447 m/s}{1 mph}[/tex]
= 8.94 [tex]m/s^{2}[/tex]
Relation between velocity, acceleration and time is as follows.
v = u + at
Putting the given values into the above formula as follows.
v = u + at
v = [tex]0 + 8.94 m/s^{2} \times 30 sec[/tex]
= 268.2 m/s
Therefore, we can conclude that at a speed of 268.2 m/s the airplane is travelling in the given situation.
