Which atoms make up the ring in the cyclic form of glucose?
A) 5 carbon atoms
B) 5 carbon atoms and 1 oxygen atom
C) 4 carbon atoms and 4 oxygen atoms
D) 6 carbon atoms

In glucose both alcohol and aldehyde groups are present within a molecule due to which molecule undergoes inter molecular reaction to give hemiacetal. This hemiacetal is six membered ring of one oxygen atom and 5 carbon atom.

In an image attached Fischer projection of D-glucose and cyclic form of α-D-glucose in shown.

Аноним Аноним · Answer 2 · 2019-11-11T09:29:52+01:00

Answer: The correct answer is Option B.

Explanation:

Glucose is an organic compound which is made up of carbon, oxygen atom hydrogen atoms. The chemical formula of glucose is [tex]C_6H_{12}O_6[/tex]

This compound contains 2 types of functional groups, which are alcohol and aldehyde.

Because of the presence of these two functional groups, the molecule undergoes inter molecular reaction to form hemiacetal. During this process, water is released.

The hemiacetal form of the molecule is known as ring form of glucose which is made up of 5 carbon atoms and 1 oxygen atom.

Hence, the correct answer is Option B.

Which atoms make up the ring in the cyclic form of glucose? A) 5 carbon atoms B) 5 carbon atoms and 1 oxygen atom C) 4 carbon atoms and 4 oxygen atoms D) 6 carbon atoms

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Which atoms make up the ring in the cyclic form of glucose?
A) 5 carbon atoms
B) 5 carbon atoms and 1 oxygen atom
C) 4 carbon atoms and 4 oxygen atoms
D) 6 carbon atoms